 | Thomas H. Palmer - 1854 - 356 pages
...other. The side A 0, opposite the right angle, is called the hypothenuse. It is shown by Geometry, that the square of the hypothenuse is equal to the sum of the squares of the other two sides. It follows that the difference between the square of the hypothenuse... | |
 | Thomas H. Palmer - 1854 - 368 pages
...other. The side AC, opposite the right angle, is called the hypothenuse. It is shown by Geometry, that the square of the hypothenuse is equal to the sum of the squares of the other two sides. It follows that the difference between the square of the hypothenuse... | |
 | Thomas Kentish - 1854 - 268 pages
...29, and raise a perpendicular BC = 17. Join AB; apply it to the scale, and it will be found 33.6. For the square of the hypothenuse is equal to the sum of the squares of the base and perpendicular. It- is required to find the diameter of a copper, that, being... | |
 | Thomas Lund - 1854 - 520 pages
...be used sometimes conveniently for constructing a right angle. For from (43, Part I.) we know, that the square of the hypothenus'e is equal to the sum of the squares of the other sides in a right-angled triangle. Take, then, 12 links of the chain, and having... | |
 | James William M'Gauley - 1854 - 284 pages
...of the hypothenuse and the other small «2 _ nZ side b is *, b is equal to — — - — For, since the square of the hypothenuse is equal to the sum of the squares of the small sides, 2sb=s2— a2 6=£2_o2 26. If the diagonal of a rectangle is c, and the... | |
 | 1855 - 424 pages
...two sides of a right-angled triangle are given, the third may be found by means of the property that the square of the hypothenuse is equal to the sum of the squares of the other two sides. Hence h = Ъ = —p = ^h' — b* Ex. 1. If the base is 2720, and the... | |
 | Elias Loomis - 1855 - 192 pages
...two sides of a right-angled triangle are given, the third may be found by means of the property that the square of the hypothenuse is equal to the sum of the squares of the other two sides. ,, Hence, representing the hypothenuse, base, and perpendicular by... | |
 | William Smyth - 1855 - 234 pages
...the third. This case may be solved by means of the known property of a right angled triangle, viz. the square of the hypothenuse is equal to the sum of the squares of the two sides. It may, moreover, be solved with facility by means of the two propositions,... | |
 | John Fair Stoddard - 1856 - 312 pages
...side can be found by means of the following theorem. It is an established theorem of geometry, that the square of the hypothenuse is equal to the sum of the SQUARES of the ntlier two sides. Therefore, the square of one of the sides is equal to tlie square... | |
 | Jaime Luciano Balmes - 1856 - 548 pages
...requires reasoning. That the whole is greater than its part is evident by immediate evidence ; that the square of the hypothenuse is equal to the sum of the squares of the other two sides, is known by mediate evidence, that is, by demonstrative reasoning.... | |
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... the square of the hypothenuse is equal to the sum of the squares of the other two sides. 
